2[4(x-1)+1]=

Solution for 2[4(x-1)+1]= equation:

Simplifying
2[4(x + -1) + 1] = 0

Reorder the terms:
2[4(-1 + x) + 1] = 0
2[(-1 * 4 + x * 4) + 1] = 0
2[(-4 + 4x) + 1] = 0

Reorder the terms:
2[-4 + 1 + 4x] = 0

Combine like terms: -4 + 1 = -3
2[-3 + 4x] = 0
[-3 * 2 + 4x * 2] = 0
[-6 + 8x] = 0

Solving
-6 + 8x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 8x = 0 + 6

Combine like terms: -6 + 6 = 0
0 + 8x = 0 + 6
8x = 0 + 6

Combine like terms: 0 + 6 = 6
8x = 6

Divide each side by '8'.
x = 0.75

Simplifying
x = 0.75